Which of the following equations represents a line that is parallel to y = 3x +2and passes through the point, (1,6)?

Accepted Solution

Answer:y=3x+3 is slope-intercept formy-6=3(x-1) is point-slope formI don't know the form your equation(s) are in. There are other forms.Step-by-step explanation:The slope-intercept form a line is y=mx+b where m is the slope and b is the y-intercept.So the slope of y=3x+2 is 3.Parallel lines have the same slope.  So the slope of the line we are looking for has a slope of 3.Therefore, our equation his this form y=3x+b.We need to now find b.We know a point (x,y) on the line.y=3x+b using (x,y)=(1,6).6=3(1)+b6=3+bSubtract 3 on both sides:3=bSo the equation is y=3x+3Point-slope form is another form we can put our line intoy-y1=m(x-x1)where m is the slope and (x1,y1) is a point on the line.We have m=3 and a point (x1,y1) on the line is (1,6).y-6=3(x-1)