Find the length of the rectangle with pythagoras You can use point (0,0) and (3,3) as the reference points. l = √(Δx² + Δy²) l = √((3-0)² + (3-0)²) l = √(3² + 3²) l = √18
Find the width of the rectangle with pythagoras You can use point (0,0) and (2,-2) as the reference points. w = √(Δx² + Δy²) w = √((-2-0)² + (2-0)²) w = √((-2)² + 2²) w = √(4 + 4) w = √8
Find the area of rectangle A = l × w A = √18 × √8 A = √9 × √2 × √4 × √2 A = 3 × √2 × 2 × √2 A = 12